# Surviving on \$100

Mar 11, 2008 6:00 PM

Keno Lil | Our question this week is, given a \$100 bankroll, a certain house percentage, and a certain priced ticket, how many games can we play before our bankroll is consumed?

The answer is easily computed using the formula: Bankroll divided by PC x amount bet equals Average games to depletion

For those of you who do not want to do this calculation, I have provided a chart here to save work:

 PC= 25% 26% 27% 28% 29% 30% Bet Games to Bankruptcy \$1.00 400 385 370 357 345 333 \$1.50 267 256 247 238 230 222 \$2.00 200 192 185 179 172 167 \$2.50 160 154 148 143 138 133 \$3.00 133 128 123 119 115 111 \$3.50 114 110 106 102 99 95 \$4.00 100 96 93 89 86 83 \$4.50 89 85 82 79 77 74 \$5.00 80 77 74 71 69 67 \$5.50 73 70 67 65 63 61 \$6.00 67 64 62 60 57 56 \$6.50 62 59 57 55 53 51 \$7.00 57 55 53 51 49 48 \$7.50 53 51 49 48 46 44 \$8.00 50 48 46 45 43 42 \$8.50 47 45 44 42 41 39 \$9.00 44 43 41 40 38 37 \$9.50 42 40 39 38 36 35 \$10.00 40 38 37 36 34 33

The above figures represent mathematical averages over millions of games and do not necessarily reflect the real life experience of keno players. Although it is true that a keno player playing a \$1 (30 percent) ticket on a \$100 bankroll can expect to play 333 games before going broke, it is highly unlikely that he will.

It is indisputable that the more games of keno you play, the higher your chance of hitting a big winner.

Keno Lil rates low cost, low PCT tickets:

on a scale of five, with five being highest!

The above formula will work for any casino game. If you are playing a 25-cent video poker game with a 2 percent house edge, \$1.25 per hand, and your bankroll is \$100, you can expect, on average, to play 4,000 hands before going broke.

For any Keno questions, write me c/o GamingToday, or email me on the web at [email protected].