Surviving on $100

March 11, 2008 6:00 PM
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Keno Lil | Our question this week is, given a $100 bankroll, a certain house percentage, and a certain priced ticket, how many games can we play before our bankroll is consumed?

The answer is easily computed using the formula: Bankroll divided by PC x amount bet equals Average games to depletion

For those of you who do not want to do this calculation, I have provided a chart here to save work:

PC=
25%
26%
27%
28%
29%
30%
Bet
Games to Bankruptcy
$1.00
400
385
370
357
345
333
$1.50
267
256
247
238
230
222
$2.00
200
192
185
179
172
167
$2.50
160
154
148
143
138
133
$3.00
133
128
123
119
115
111
$3.50
114
110
106
102
99
95
$4.00
100
96
93
89
86
83
$4.50
89
85
82
79
77
74
$5.00
80
77
74
71
69
67
$5.50
73
70
67
65
63
61
$6.00
67
64
62
60
57
56
$6.50
62
59
57
55
53
51
$7.00
57
55
53
51
49
48
$7.50
53
51
49
48
46
44
$8.00
50
48
46
45
43
42
$8.50
47
45
44
42
41
39
$9.00
44
43
41
40
38
37
$9.50
42
40
39
38
36
35
$10.00
40
38
37
36
34
33

The above figures represent mathematical averages over millions of games and do not necessarily reflect the real life experience of keno players. Although it is true that a keno player playing a $1 (30 percent) ticket on a $100 bankroll can expect to play 333 games before going broke, it is highly unlikely that he will.

It is indisputable that the more games of keno you play, the higher your chance of hitting a big winner.

Keno Lil rates low cost, low PCT tickets:

on a scale of five, with five being highest!

The above formula will work for any casino game. If you are playing a 25-cent video poker game with a 2 percent house edge, $1.25 per hand, and your bankroll is $100, you can expect, on average, to play 4,000 hands before going broke.

For any Keno questions, write me c/o GamingToday, or email me on the web at kenolil@gmail.com.