# 63 ways to win a jackpot

Sep 7, 2004 3:10 AM

This week we’ll talk about one of my favorite tickets. This ticket is marked using 15 numbers, grouped 3-3-3-2-2-2. We know from our previous discussions that this ticket, since it has six groups on it, has a total of 63 ways. Using the abbreviated bridge system that we learned a couple of weeks ago, we can split the ticket into two slices, 3-3-3 and 2-2-2. The 3-3-3 gives us a one way nine, a three way six, and a three way three. The 2-2-2 gives us a one way six, a three way four and a three way two. Thus the table below, using the abbreviated bridge system:

 1/9 3/6 3/3 1/6 1/15 3/12 3/9 3/4 3/13 9/10 9/7 3/2 3/11 9/8 9/5

Remember, once we’ve split the ticket, we multiply the numerator and add the denominator. This process gives us all the ways on the ticket.

This week we’ll consider the five spot ways, since you all know that I am a big fan of five spots. I’ll play the 15 spot as well, for coverage. We need to cover all the spots on the ticket, because after all, it is possible to hit 12 out of the fifteen numbers without hitting a solid five! Doing so will give us a ten-way ticket, and we can play it for ten dollars at a dollar a way, five dollars at fifty cents per way, or even a dollar at the Keno games that will let us play for a dime a way.

This ticket is particularly easy to check using the bridge system. Suppose that we play the ticket and we get the following catch:

 Group: 3 3 3 2 2 2 Catch: 3 2 0 2 1 1

We can see by inspection that the ticket has a catch of 9 out of 15, which will already make our day. The bridge system may be used to check this ticket by writing the catches on the three spots on the top line of a table, and by writing the catches on the two spots down the first column. The table is completed by simple addition of rows and columns, to wit:

 3 2 0 2 5 4 2 1 4 3 1 1 4 3 1

In this case, where we are checking a ticket for winners, and not breaking out the ways, we ignore the top row and the initial column. We are lucky, we have one solid five, three four out of fives, and two three out of fives! Since the five-spot typically pays off at odds of 800 or so to one, and 9 out of 15 pays off a typical 100 to one, and we are playing ten units per game, this catch should pay off at least 90 to one at most keno games based on our wager. A good catch!

This ticket is full of interesting features aside from the five spots. We’ll cover some of them next week. Well, that’s it for now. Good luck! I’ll see you in line!